Integrand size = 29, antiderivative size = 29 \[ \int \frac {\sinh (c+d x)}{(e+f x)^2 (a+i a \sinh (c+d x))} \, dx=\text {Int}\left (\frac {\sinh (c+d x)}{(e+f x)^2 (a+i a \sinh (c+d x))},x\right ) \]
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Not integrable
Time = 0.03 (sec) , antiderivative size = 29, normalized size of antiderivative = 1.00, number of steps used = 0, number of rules used = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \frac {\sinh (c+d x)}{(e+f x)^2 (a+i a \sinh (c+d x))} \, dx=\int \frac {\sinh (c+d x)}{(e+f x)^2 (a+i a \sinh (c+d x))} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {\sinh (c+d x)}{(e+f x)^2 (a+i a \sinh (c+d x))} \, dx \\ \end{align*}
Not integrable
Time = 29.54 (sec) , antiderivative size = 31, normalized size of antiderivative = 1.07 \[ \int \frac {\sinh (c+d x)}{(e+f x)^2 (a+i a \sinh (c+d x))} \, dx=\int \frac {\sinh (c+d x)}{(e+f x)^2 (a+i a \sinh (c+d x))} \, dx \]
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Not integrable
Time = 0.46 (sec) , antiderivative size = 27, normalized size of antiderivative = 0.93
\[\int \frac {\sinh \left (d x +c \right )}{\left (f x +e \right )^{2} \left (a +i a \sinh \left (d x +c \right )\right )}d x\]
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Not integrable
Time = 0.24 (sec) , antiderivative size = 232, normalized size of antiderivative = 8.00 \[ \int \frac {\sinh (c+d x)}{(e+f x)^2 (a+i a \sinh (c+d x))} \, dx=\int { \frac {\sinh \left (d x + c\right )}{{\left (f x + e\right )}^{2} {\left (i \, a \sinh \left (d x + c\right ) + a\right )}} \,d x } \]
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Not integrable
Time = 22.54 (sec) , antiderivative size = 631, normalized size of antiderivative = 21.76 \[ \int \frac {\sinh (c+d x)}{(e+f x)^2 (a+i a \sinh (c+d x))} \, dx=- \frac {2}{- i a d e^{2} - 2 i a d e f x - i a d f^{2} x^{2} + \left (a d e^{2} e^{c} + 2 a d e f x e^{c} + a d f^{2} x^{2} e^{c}\right ) e^{d x}} - \frac {i \left (\int \left (- \frac {4 i f}{e^{3} e^{c} e^{d x} - i e^{3} + 3 e^{2} f x e^{c} e^{d x} - 3 i e^{2} f x + 3 e f^{2} x^{2} e^{c} e^{d x} - 3 i e f^{2} x^{2} + f^{3} x^{3} e^{c} e^{d x} - i f^{3} x^{3}}\right )\, dx + \int \left (- \frac {i d e}{e^{3} e^{c} e^{d x} - i e^{3} + 3 e^{2} f x e^{c} e^{d x} - 3 i e^{2} f x + 3 e f^{2} x^{2} e^{c} e^{d x} - 3 i e f^{2} x^{2} + f^{3} x^{3} e^{c} e^{d x} - i f^{3} x^{3}}\right )\, dx + \int \left (- \frac {i d f x}{e^{3} e^{c} e^{d x} - i e^{3} + 3 e^{2} f x e^{c} e^{d x} - 3 i e^{2} f x + 3 e f^{2} x^{2} e^{c} e^{d x} - 3 i e f^{2} x^{2} + f^{3} x^{3} e^{c} e^{d x} - i f^{3} x^{3}}\right )\, dx + \int \frac {d e e^{c} e^{d x}}{e^{3} e^{c} e^{d x} - i e^{3} + 3 e^{2} f x e^{c} e^{d x} - 3 i e^{2} f x + 3 e f^{2} x^{2} e^{c} e^{d x} - 3 i e f^{2} x^{2} + f^{3} x^{3} e^{c} e^{d x} - i f^{3} x^{3}}\, dx + \int \frac {d f x e^{c} e^{d x}}{e^{3} e^{c} e^{d x} - i e^{3} + 3 e^{2} f x e^{c} e^{d x} - 3 i e^{2} f x + 3 e f^{2} x^{2} e^{c} e^{d x} - 3 i e f^{2} x^{2} + f^{3} x^{3} e^{c} e^{d x} - i f^{3} x^{3}}\, dx\right )}{a d} \]
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Not integrable
Time = 0.30 (sec) , antiderivative size = 194, normalized size of antiderivative = 6.69 \[ \int \frac {\sinh (c+d x)}{(e+f x)^2 (a+i a \sinh (c+d x))} \, dx=\int { \frac {\sinh \left (d x + c\right )}{{\left (f x + e\right )}^{2} {\left (i \, a \sinh \left (d x + c\right ) + a\right )}} \,d x } \]
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Not integrable
Time = 0.37 (sec) , antiderivative size = 29, normalized size of antiderivative = 1.00 \[ \int \frac {\sinh (c+d x)}{(e+f x)^2 (a+i a \sinh (c+d x))} \, dx=\int { \frac {\sinh \left (d x + c\right )}{{\left (f x + e\right )}^{2} {\left (i \, a \sinh \left (d x + c\right ) + a\right )}} \,d x } \]
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Not integrable
Time = 1.02 (sec) , antiderivative size = 30, normalized size of antiderivative = 1.03 \[ \int \frac {\sinh (c+d x)}{(e+f x)^2 (a+i a \sinh (c+d x))} \, dx=\int \frac {\mathrm {sinh}\left (c+d\,x\right )}{{\left (e+f\,x\right )}^2\,\left (a+a\,\mathrm {sinh}\left (c+d\,x\right )\,1{}\mathrm {i}\right )} \,d x \]
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